-16t^2+256t=768

Solution for -16t^2+256t=768 equation:

-16t^2+256t=768

We move all terms to the left:

-16t^2+256t-(768)=0

a = -16; b = 256; c = -768;
Δ = b2-4ac
Δ = 2562-4·(-16)·(-768)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(256)-128}{2*-16}=\frac{-384}{-32}
=+12
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(256)+128}{2*-16}=\frac{-128}{-32}
=+4
$